N dimensional cartesian product of a set in julia

When working with sets in Julia, it is often necessary to find the N-dimensional cartesian product of a given set. The cartesian product is a mathematical operation that returns a set from multiple sets, where each element in the resulting set is a combination of elements from the input sets. In this article, we will explore three different ways to compute the N-dimensional cartesian product in Julia.

Option 1: Using nested loops

One way to compute the N-dimensional cartesian product is by using nested loops. We can iterate over each element in each set and combine them to form the cartesian product. Here is an example implementation:


function cartesian_product(sets)
    if isempty(sets)
        return Set{Tuple}()
    end
    
    result = Set{Tuple}()
    for element in first(sets)
        if length(sets) == 1
            push!(result, (element,))
        else
            remaining_sets = sets[2:end]
            for tuple in cartesian_product(remaining_sets)
                push!(result, (element, tuple...))
            end
        end
    end
    
    return result
end

sets = [[1, 2], [3, 4], [5, 6]]
cartesian_product(sets)

This implementation uses recursion to handle sets of any dimension. It starts by checking if the input sets are empty, in which case it returns an empty set. Otherwise, it initializes an empty set to store the cartesian product. It then iterates over the elements of the first set and recursively computes the cartesian product of the remaining sets. Finally, it combines each element from the first set with each tuple from the cartesian product of the remaining sets and adds them to the result set.

Option 2: Using the IterTools.jl package

Another way to compute the N-dimensional cartesian product is by using the IterTools.jl package. This package provides a convenient function called `product` that can be used to compute the cartesian product of multiple sets. Here is an example implementation:


using IterTools

sets = [[1, 2], [3, 4], [5, 6]]
result = collect(product(sets...))

This implementation is much simpler and more concise compared to the previous one. It uses the `product` function from the IterTools.jl package to compute the cartesian product of the input sets. The `product` function takes multiple sets as arguments and returns an iterator over the cartesian product. We can then collect the iterator into a set or any other desired data structure.

Option 3: Using a combination of comprehensions and `reduce`

A third way to compute the N-dimensional cartesian product is by using a combination of comprehensions and the `reduce` function. Here is an example implementation:


sets = [[1, 2], [3, 4], [5, 6]]
result = reduce((x, y) -> [a*b for a in x, b in y], sets)

This implementation uses a comprehension to generate the cartesian product of each pair of sets. It then uses the `reduce` function to combine the cartesian products of all pairs of sets into a single cartesian product. The `reduce` function takes a binary function and an iterable as arguments, and applies the function to the elements of the iterable in a cumulative way.

After exploring these three options, it is clear that the second option, using the IterTools.jl package, is the most efficient and concise way to compute the N-dimensional cartesian product in Julia. It provides a dedicated function that handles the cartesian product computation efficiently, without the need for complex recursive or comprehension-based implementations. Therefore, using the IterTools.jl package is the recommended approach for computing the N-dimensional cartesian product in Julia.

Rate this post

Leave a Reply

Your email address will not be published. Required fields are marked *

Table of Contents